This week problem is.
A square has coordinates A(0; 0), B(-9; 12), C(3; 21) and D(12; 9). The line l passes through A and intersects CD at point T(r; s) splitting the square so that the area of square ABCD is three times the area of triangle ATD. Determine the equation of line l.
Because the area of triangle ATD is 1/3 of the square, and area of triangle ACD if 1/2 of the square, these mean DT : CD = 2 : 3. And CT = CD - DT, then the ratio of CT : TD = 1 : 2.
Using the ratio we have equations:
$ (3 - r) : (r - 12) = 1 : 2 $
$ (21 - s) : (s - 9) = 1 : 2 $.
Change them to fraction form are:
$ \frac{3-r}{r-21} = \frac{1}{2}$
$ \frac{21-s}{s-9} = \frac{1}{2}$
Solve them will get the values of r and s.